Respuesta :
Answer:
The distance traveled by the skier is 5.309 km
Solution:
As per the question:
Mass of the skier, m = 64 kg
Coefficient of friction between the ski and the snow, [tex]\mu_{k} = 0.50[/tex]
Mass of snow, M = 5.0 kg
Now,
To calculate the distance, 's' traveled by the skier, in order to melt 5.0 kg of snow:
We know that:
[tex]f = \mu_{k}N[/tex]
where
[tex]\mu_{k}[/tex] = coefficient of friction
N = Normal Reaction
N = mg
Thus
[tex]f = \mu_{k}mg[/tex] (1)
Also,
[tex]fs = ML_{f}[/tex] (2)
where
[tex]L_{f} = 3.33\times 10^{5}\ J/kg[/tex] = Latent Heat of fusion
Thus from eqn (1) and (2):
[tex]s = \frac{ML_{f}}{\mu_{k}mg}[/tex]
[tex]s = \frac{5\times 3.33\times 10^{5}}{0.50\times 64\times 9.8}[/tex]
s = 5.309 km
