Answer:
3100.05 N
Explanation:
[tex]F_1[/tex] = Force applied = 45 N
[tex]\dfrac{r_2}{r_1}=8.3[/tex]
From Pascal's law we have
[tex]\dfrac{F_1}{F_2}=\dfrac{A_1}{A_2}\\\Rightarrow \dfrac{F_1}{F_2}=\dfrac{\pi r_1^2}{\pi r_2^2}\\\Rightarrow F_2=F_1\dfrac{r_2^2}{r_1^2}\\\Rightarrow F_2=45\times 8.3^2\\\Rightarrow F_2=3100.05\ N[/tex]
The force on the output plunger is 3100.05 N