Respuesta :
Answer:
[tex]7.78\ m/s[/tex] is the 80 kg players velocity after the bump.
Explanation:
Given the mass and velocity of players.
Velocity before collision is [tex]10\ m/s\ and\ 8\ m/s[/tex] for [tex]80[/tex] kg and [tex]100[/tex] kg player respectively.
And velocity after collision is [tex]v_1[/tex] for [tex]80[/tex] kg player and [tex]9.78\ m/s[/tex] for [tex]100[/tex] kg player
We will apply principle of conservation of momentum.
Momentum[tex]=(mass)\times(velocity)[/tex]
So, momentum before collision is [tex](80\times10)+(100\times8)[/tex]
And momentum after collision is [tex](80\times v_1)+(100\times 9.78)[/tex]
That is momentum before collision should equal momentum after collision.
[tex](80\times10)+(100\times8)=(80\times v_1)+(100\times 9.78)\\\\800+800=80\times v_1+978\\1600=80\times v_1+978\\1600-978=80\times v_1\\622=80\times v_1\\\frac{622}{80}=v_1\\ v_1=7.775[/tex]
[tex]v_1=7.775[/tex]≅[tex]7.78\ m/s[/tex]
