Answer:
Explanation:
Given
Grating Width [tex]w=75 mm[/tex]
no of lines [tex]N=50,000 lines[/tex]
inclination of second order maxima [tex]\theta =32.5^{\circ}[/tex]
Condition of maxima For Diffraction grating
[tex]d\sin \theta =m\lambda [/tex]
where [tex]d=Grating\ constant[/tex]
[tex]\lambda =wavelength[/tex]
[tex]m=order\ of\ maxima[/tex]
[tex]d=\frac{width}{N}[/tex]
[tex]d=\frac{75}{50,000}[/tex]
[tex]d=0.0015\ mm[/tex]
therefore for second order maxima wavelength of light is given by
[tex]\lambda =\frac{d\sin \theta }{m}[/tex]
[tex]\lambda =\frac{0.0015\times \sin (32.5)}{2}[/tex]
[tex]\lambda =403\times 10^{-6}\ m[/tex]
[tex]\lambda =403\ nm[/tex]
