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A car goes around a curve of radius r at a constant speed v. Then it goes around a curve of radius 2r at speed 2v. What is the centripetal acceleration on the car as it goes around the second curve, compared to the first?

Respuesta :

Answer:

[tex]a'=2\times a[/tex]

Explanation:

given,

first case

car speed = v

radius of curve = r

second case

car speed (v')= 2 v

radius of curve (r')=2 r

centripetal acceleration of car is given by

[tex]a=\dfrac{v^2}{r}[/tex]

for second case

[tex]a'=\dfrac{v'^2}{r'}[/tex]

[tex]a'=\dfrac{(2v)^2}{2r}[/tex]

[tex]a'=2\dfrac{v^2}{r}[/tex]

[tex]a'=2\times a[/tex]

Hence, the centripetal acceleration on the second case is twice of first case.

Answer:2v^2/r

Explanation: