Answer : The mass of sucrose added to 375 mL of water must be, 10.6 grams.
Explanation :
As we are given that 2.75 m/m percent solution of sucrose. That means, 2.75 grams of sucrose present in 100 grams of solution.
Mass of solution = 100 g
Mass of sucrose = 2.75 g
Mass of water = Mass of solution - Mass of sucrose
Mass of water = 100 g - 2.75 g
Mass of water = 97.25 g
First we have to calculate the mass of water.
[tex]\text{Mass of water}=\text{Density of water}\times \text{Volume of water}[/tex]
Density of water = 1.00 g/mL
Volume of water = 375 mL
[tex]\text{Mass of water}=1.00g/mL\times 375mL=375g[/tex]
Now we have to calculate the mass of sucrose in 375 g of water.
As, 97.25 grams of water contain 2.75 grams of sucrose
So, 375 grams of water contain [tex]\frac{375}{97.25}\times 2.75=10.6[/tex] grams of sucrose
Therefore, the mass of sucrose added to 375 mL of water must be, 10.6 grams.
