Answer: The mass of ice cube is 77.90 grams
Explanation:
When ice is mixed with water, the amount of heat released by ice will be equal to the amount of heat absorbed by water.
[tex]Heat_{\text{absorbed}}=Heat_{\text{released}}[/tex]
The equation used to calculate heat released or absorbed follows:
[tex]Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})[/tex]
[tex]m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)][/tex] ......(1)
where,
[tex]m_1[/tex] = mass of ice = ? g
[tex]m_2[/tex] = mass of water = 30.0 g
[tex]T_{final}[/tex] = final temperature = 19.5°C
[tex]T_1[/tex] = initial temperature of ice = 0.0°C
[tex]T_2[/tex] = initial temperature of water = 45.0°C
[tex]c_1[/tex] = specific heat of ice = 2.108 J/g°C
[tex]c_2[/tex] = specific heat of water = 4.186 J/g°C
Putting values in equation 1, we get:
[tex]m_1\times 2.108\times (19.5-0)=-[30.0\times 4.186\times (19.5-45.0)][/tex]
[tex]m_1=77.90g[/tex]
Hence, the mass of ice cube is 77.90 grams