A group of 10 fisherman enjoy certain types of fish, 3 of them like salmon, 5 like trout and 2 like bass. A single fisherman is chosen at random. What is the probability that the fisherman likes salmon or bass?

Respuesta :

Answer:

[tex]P(salmon or bass)=\frac{1}{2}[/tex]

Step-by-step explanation:

A group of 10 fisherman enjoy certain types of fish, 3 of them like salmon, 5 like trout and 2 like bass.

P(event)= number of outcomes divide by total outcomes

[tex]P(salmon)=\frac{3}{10}[/tex]

[tex]P(bass)=\frac{2}{10}=\frac{1}{5}[/tex]

[tex]P(salmon or bass)=\frac{3}{10}+\frac{2}{10}=\frac{5}{10}=\frac{1}{2}[/tex]