Respuesta :
Answer:
A) Adding [tex]H_2SO_4[/tex]
B) Adding [tex]HI[/tex]
Explanation:
A) Adding [tex]H_2SO_4[/tex]
1) [tex]H_2SO_4 + 2 AgNO_3 \longrightarrow Ag_2SO_4 +2 HNO_3[/tex]
2) [tex]H_2SO_4 + Cu(NO_3)_2 \longrightarrow CuSO_4 +2 HNO_3[/tex]
[tex]CuSO_4[/tex] is very soluble in water and, in the other hand, [tex]Ag_2SO_4[/tex] is not.
B) Adding [tex]HI[/tex]
1) [tex]2 HI + MgCl_2 \longrightarrow MgI_2 + 2 HCl[/tex]
2) [tex]2 HI + CuCl_2 \longrightarrow CuI_2 + 2 HCl[/tex]
[tex]MgI_2 [/tex] is very soluble in water and, in the other hand, [tex]CuI_2[/tex] is not.
Answer:
HCl and H2S
HCl + AgNO3 ---> (HNO3) + AgCl.
Agcl is white in color and is formed by the reaction between colorless aqueous silver nitrateto a colorless solution solution of sodium chloride to produce an opaque white precipitate
H2S + CuCl2 ----- > CuS + HCl
CuS It is a moderate conductor of electricity. A black colloidal precipitate of CuS is formed when hydrogen sulfide, H2S, is bubbled through solutions of Cu(II) salts
Explanation: