Explanation:
It is known that molarity is the number of moles present in a liter of solution.
Mathematically, Molarity = [tex]\frac{\text{no. of moles}}{\text{volume in liter}}[/tex]
Hence, calculate the molarity of given solution as follows.
Molarity of citric acid = [tex]\frac{\text{mass of citric acid}}{\text{molar mass of citric acid}} \times \frac{1}{\text{volume of solution(L)}}[/tex]
= [tex]\frac{25 g}{192.13 g/mol} \times \frac{1}{0.75 L}[/tex]
= 0.173 M
As citric acid is a triprotic acid so, upon dissociation it gives three hydrogen ions.
Normality = Molarity × no. of hydrogen or hydroxide ions
= 0.173 × 3
= 0.519 N
Thus, we can conclude that molarity of given solution is 0.173 and its normality is 0.519 N.
