Answer:
[tex]CH_3-CH(I)-CH(CH_3)-CH_3[/tex]
[tex]I-CH_2-CH_2-CH(CH_3)-CH_3[/tex]
Explanation:
Given the compound [tex]CH_2=CH-CH(CH_3)-CH_3[/tex]
The steps of reaction:
[tex]HI \longrightarrow H^+ + I^-[/tex]
[tex]CH_2=CH-CH(CH_3)-CH_3 + H^+ \longrightarrow CH_3-CH^+-CH(CH_3)-CH_3 [/tex]
But this intermediate product has a resonance:
[tex]CH_3-CH^+-CH(CH_3)-CH_3 \longleftrightarrow C^+H_2-CH2-CH(CH_3)-CH_3 [/tex]
The reaction with I-
[tex]CH_3-CH^+-CH(CH_3)-CH_3 + I^- \longrightarrow CH_3-CH(I)-CH(CH_3)-CH_3[/tex]
[tex]C^+H_2-CH2-CH(CH_3)-CH_3 + I^- \longrightarrow I-CH_2-CH_2-CH(CH_3)-CH_3[/tex]
