Respuesta :

Answer:

True

Step-by-step explanation:

because if you have q+i=p then that would be a true complex but in this case it would be true because of absolute value

DeanR

p=1+2i, q=1-2i,  p+q=2, pq=1²+2²=5, |p|=|q|=√5

p=3-i, q=3+i, p+q=6, pq=3²+1²=10, |p|=|q|=√10

p=-6+8i, q=-6-8i, p+q=-12, pq=(-6)²+8²=100, |p|=|q|=10

b.

The sum of conjugates is twice the real part.

The product of conjugates is the squared magnitude.

Conjugates have the same magnitude.

The difference of conjugates is 2i times the imaginary part.

c.

TRUE.

Let p=a+bi

(-p)* = (-(a+bi))* = (-a-bi)* = -a + bi

-(p*) = -(a-bi) = -a + bi

They're the same.