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In the coordination
compound[Cr(NH3)(en)2Cl]Br2,
thecoordination number (C.N.) and oxidation number (O.N.) of the
metalatom are, respectively,
A. C.N. = 6; O.N. = +4.
B. C.N. = 6; O.N. = +3.
C. C.N. = 5; O.N. = +2.
D. C.N. = 4; O.N. = +2.
E. C.N. = 4; O.N. = +3.

Respuesta :

ajinems

Answer: the correct option is A (C.N. = 6; O.N. = +4.)

Explanation:In the coordination

compound[Cr(NH3)(en)2Cl]Br2,

the coordination number (C.N.) and oxidation number (O.N.) of the

metal atom are 6 and +4 respectively.

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