contestada

What volume of carbon dioxide gas can be collected from
thereaction between 10.0 g of calcium carbonate and 100.0 mL of
0.50 Mhydrochloric acid at 25.0oC and 1.0 atm
pressure?

Respuesta :

maacastrobr

Answer:

1.22 L of carbon dioxide gas

Explanation:

The reaction that takes place is:

  • CaCO₃ + HCl → CaCl₂ + CO₂ + H₂O

First we determine which reactant is limiting:

  • Calcium carbonate ⇒ 10.0 g CaCO₃ ÷ 100 g/mol = 0.10 mol CaCO₃
  • Hydrochloric acid ⇒ 0.100 L * 0.50 M = 0.05 mol HCl

So HCl is the limiting reactant.

Now we calculate the moles of CO₂ produced:

  • 0.05 mol HCl * [tex]\frac{1molCO_{2}}{1molHCl}[/tex] = 0.05 mol CO₂

Finally we use PV=nRT to calculate the volume:

  • P = 1 atm
  • n = 0.05 mol
  • T = 25 °C ⇒ 25 + 273.16 = 298.16 K

1 atm * V = 0.05 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 298.16 K

  • V = 1.22 L