contestada

How many hours are required to produce 1.00 x
103kgof sodium by the electrolysis of molten NaCl with a
constantcurrent of 3.00 x 104 A?

Respuesta :

Answer: 42 hours  

Explanation:

Moles of electron = 1 mole

According to mole concept:

1 mole of an atom contains [tex]6.022\times 10^{23}[/tex] number of particles.

We know that:

Charge on 1 electron = [tex]1.6\times 10^{-19}C[/tex]

Charge on 1 mole of electrons = [tex]1.6\times 10^{-19}\times 6.022\times 10^{23}=96500C[/tex]

[tex]NaCl\rightarrow Na^++Cl^-[/tex]

[tex]Na^++e^-\rightarrow Na[/tex]

According to stoichiometry:

1 mole of electrons deposit = 23 g of sodium

i.e 96500 C of electricity deposit = 23 g of sodium

Thus 23 g of sodium is deposited by = 96500 C of electricity

 [tex]1.00\times 10^3kg=1.00\times 10^6g[/tex] of sodium is deposited by = [tex]\frac{96500}{23}\times 1.00\times 10^6=4.20\times 10^9[/tex] C of electricity

To calculate the time required, we use the equation:

[tex]I=\frac{q}{t}[/tex]

where,

I = current passed =[tex]3.00\times 10^4A[/tex]

q = total charge = [tex]4.20\times 10^9[/tex]

t = time in secods = ?

Putting values in above equation, we get:

[tex]3.00\times 10^4A=\frac{4.20\times 10^9}{t}[/tex]

[tex]t=1.4\times 10^5sec=42hr[/tex]      [tex](1sec= 0.0003hr[/tex]

Thus 42 hours are required.