Answer:4.05 cm/s
Explanation:
Given
Speed of goldfish towards [tex]v_1=1.2 cm/s[/tex]
Refractive index of water [tex]n_1=\frac{4}{3}[/tex]
Apparent Speed of fish can be obtained by
[tex]\frac{n_1}{v_1}+\frac{n_2}{v_2}=\frac{n_2-n_1}{R}[/tex]
where [tex]n_2=refractive\ index\ of\ air[/tex]
[tex]R=radius\ of\ curvature[/tex]
[tex]v_2=apparent\ velocity[/tex]
[tex]\frac{1.33}{1.2}+\frac{1}{v_2}=\frac{1.33-1}{\infty }[/tex]
[tex]v_2=\frac{5.4}{1.33}[/tex]
[tex]v_2=4.05 cm/s[/tex]
