Answer:
0.015 M
Explanation:
Let's consider the solution of silver (I) sulfate.
Ag₂SO₄(s) ⇄ 2 Ag⁺(aq) + SO₄²⁻(aq)
In order to find the solubility (S) of silver (I) sulfate, we will use an ICE chart.
Ag₂SO₄(s) ⇄ 2 Ag⁺(aq) + SO₄²⁻(aq)
I 0 0
C +2S +S
E 2S S
The solubility product (Ksp) is:
Ksp = 1.4 × 10⁻⁵ = [Ag⁺]².[SO₄²⁻] = (2S)².S = 4S³
S = 0.015 M
