Respuesta :
Answer : The number of grams of oxygen react must be, 170.4 grams.
Solution : Given,
Mass of [tex]C_3H_8[/tex] = 46.85 g
Molar mass of [tex]C_3H_8[/tex] = 44 g/mole
Molar mass of [tex]O_2[/tex] = 32 g/mole
First we have to calculate the moles of [tex]C_3H_8[/tex].
[tex]\text{ Moles of }C_3H_8=\frac{\text{ Mass of }C_3H_8}{\text{ Molar mass of }C_3H_8}=\frac{46.85g}{44g/mole}=1.065moles[/tex]
Now we have to calculate the moles of [tex]O_2[/tex]
The balanced chemical reaction is,
[tex]C_3H_8+5O_2\rightarrow 3CO_2+4H_2O[/tex]
From the balanced reaction we conclude that
As, 1 mole of [tex]C_3H_8[/tex] react with 5 mole of [tex]O_2[/tex]
So, 1.065 moles of [tex]C_3H_8[/tex] react with [tex]1.065\times 5=5.325[/tex] moles of [tex]O_2[/tex]
Now we have to calculate the mass of [tex]O_2[/tex]
[tex]\text{ Mass of }O_2=\text{ Moles of }O_2\times \text{ Molar mass of }O_2[/tex]
[tex]\text{ Mass of }O_2=(5.325moles)\times (32g/mole)=170.4g[/tex]
Therefore, the number of grams of oxygen react must be, 170.4 grams.
