Answer:
20.10 pounds of carbon dioxide are produced from burning one gallon of gasoline.
Explanation:
Volume of the gasoline = V = 1 gal = 3785.41 mL
Density of the gasoline = d = 0.78 g/ml
Mass of gasoline = m = ?
[tex]m=d\times V=0.78 g/mL\times 3785.41 mL=2952.62 g[/tex]
Moles of gasoline = [tex]\frac{2952.62 g}{114 g/mol}=25.90 mol[/tex]
[tex]2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O[/tex]
According to reaction, 2 moles of octane gives 16 moles of carbon dioxide gas.
Then 25.90 moles of octane will give:
[tex]\frac{16}{2}\times 25.90 mol=207.20 mol[/tex]
Mass of 207.20 moles of carbon dioxide gas:
= 207.20 mol × 44 g/mol = 9,116.86 g
1 pound = 453.592 grams
[tex]9,116.86 g=\frac{9,116.86}{453.592} pounds=20.10 pounds[/tex]
20.10 pounds of carbon dioxide are produced from burning one gallon of gasoline.