Answer:
a) 2/2 + 2/2 = 2
b) 2/2 + 1/2 = 3/2
c) 2/2 + 0/2 = 1
d) 0/2 + 0/2 = 0
Step-by-step explanation:
a) 2 points : 2/2 + 2/2 = 2
if henry wins both games than we get probability =2
b) 1 1/2 or 3/2 : 2/2 + 1/2 = 3/2
if henry wins one game and tie another game we get probability =3/2
c) 1 point: 2/2 + 0/2 = 1
if henry wins one game and loose second game, we get probability 1
d) 0 points: 0/2 + 0/2 = 0
if henry loose both games we get probability 0
Answer:
a) for 2 points,
Pa = Pww = 0
b) for 1.5 point,
Pb = Pwt + Ptw = 0 + 0 = 0
c) for 1 point
Pc = Pwl + Ptt + Plw = 0 + 0.64 + 0 = 0.64
d) for 0.5 point
Pd = Ptl + Plt = 0.16 + 0.16 = 0.32
e) for 0 point
Pe = Pll = 0.04
Step-by-step explanation:
The remaining part of the question is attached.
Given;
According to the rules of the game
Win = 1 point
Tie = 1/2 point
Lose= 0 point
If henry play the game conservatively, the probability of
Win = 0
Tie = 0.8
Lose = 0.2
Playing the game twice and conservatively, the following outcomes are possible with the corresponding points and probabilities.
ww = 2 points Pww = 0 × 0 = 0
wt = 1.5 point Pwt = 0 × 0.8 = 0
wl = 1 point Pwl = 0 × 0.2 = 0
tw = 1.5 point Ptw = 0.2 × 0 = 0
tt = 1 point Ptt = 0.8 × 0.8 = 0.64
tl = 0.5 point Ptl = 0.8 × 0.2 = 0.16
lw = 1 point Plw = 0.2 × 0 = 0
lt = 0.5 point Plt = 0.2 × 0.8 = 0.16
ll = 0 point Pll = 0.2 × 0.2 = 0.04
Where w = win , t = tie and l = lose.
a) for 2 points,
Pa = Pww = 0
b) for 1.5 point,
Pb = Pwt + Ptw = 0 + 0 = 0
c) for 1 point
Pc = Pwl + Ptt + Plw = 0 + 0.64 + 0 = 0.64
d) for 0.5 point
Pd = Ptl + Plt = 0.16 + 0.16 = 0.32
e) for 0 point
Pe = Pll = 0.04
