Answer:
6.12 mol
Explanation:
Let's consider the following balanced equation.
C₄H₁₀ + 6.5 O₂ → 4 CO₂ + 5 H₂O
We can establish the following relations.
The moles of oxygen needed to react with 54.7 g of butane are:
[tex]54.7gButane.\frac{1molButane}{58.12gButane}.\frac{6.5molOxygen}{1molButane} =6.12molOxygen[/tex]