Balance the equation below and use it to answer thefollowing
questions.


C4H10 + O2 ==> CO2
+H2O


How many moles of oxygen are needed to react with 54.7 g
ofbutane?

Respuesta :

Answer:

6.12 mol

Explanation:

Let's consider the following balanced equation.

C₄H₁₀ + 6.5 O₂ → 4 CO₂  + 5 H₂O

We can establish the following relations.

  • The molar mass of butane is 58.12 g/mol.
  • The molar ratio of butane to oxygen is 1:6.5.

The moles of oxygen needed to react with 54.7 g of butane are:

[tex]54.7gButane.\frac{1molButane}{58.12gButane}.\frac{6.5molOxygen}{1molButane} =6.12molOxygen[/tex]