Answer:
41.6 g
Explanation:
Calculation of the moles of [tex]SO_2[/tex] as:-
Mass = 83.2 g
Molar mass of [tex]SO_2[/tex] = 64.066 g/mol
The formula for the calculation of moles is shown below:
[tex]moles = \frac{Mass\ taken}{Molar\ mass}[/tex]
Thus,
[tex]Moles= \frac{83.2\ g}{64.066\ g/mol}[/tex]
[tex]Moles_{SO_2}= 1.2987\ mol[/tex]
From seen from the formula,
1 mole of sulfur is present in 1 mole of [tex]SO_2[/tex]
So,
1.2987 mole of sulfur is present in 1.2987 mole of [tex]SO_2[/tex]
Moles of sulfur = 1.2987 mol
Molar mass of sulfur = 32.065 g/mol
Mass = Moles*Molar mass = [tex]1.2987\times 32.065\ g[/tex] = 41.6 g
