Answer:
8, 9 and 10
Step-by-step explanation:
We would have to find the 3 consecutive integers.
Consecutive integers are one after another, such as:
1, 2, 3, ... etc.
So, if we let the first integer be "x", the next one is 1 unit apart, so next one would be:
x + 1
Next one:
x + 2
So, we have 3 consecutive integers:
x, x + 1, x + 2
It is given, 3 times smallest (x) is 14 MORE THAN largest (x + 2). So we can write:
3x = x + 2 + 14
Now we solve for x:
[tex]3x = x + 2 + 14\\3x=x+16\\3x-x=16\\2x=16\\x=\frac{16}{2}\\x=8[/tex]
So, the integers are:
8, 9 and 10
