The average angular acceleration is [tex]0.98 rad/s^2[/tex]
Explanation:
The angular acceleration of an object in circular motion is given by:
[tex]\alpha = \frac{\omega_f - \omega_i}{t}[/tex]
where
[tex]\omega_f[/tex] is the final angular speed
[tex]\omega_i[/tex] is the initial angular speed
t is the time elapsed
For the skater in this problem, we have:
[tex]\omega_i = 3.67 rad/s[/tex] (initial angular speed)
[tex]\omega_f = 8.57 rad/s[/tex] (final angular speed)
t = 5.0 s (time elapsed)
Substituting, we find the average angular acceleration:
[tex]\alpha = \frac{8.57-3.67}{5.0}=0.98 rad/s^2[/tex]
Learn more about circular motion:
brainly.com/question/2562955
brainly.com/question/6372960
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