Answer:
The vertical asymptotes are x = 2 and x = -2.
The horizontal asymptote is y = 3.
Step-by-step explanation:
Given the function
[tex]f(x)=\dfrac{3x^2}{x^2-4}[/tex]
Rewrite it as follows:
[tex]f(x)\\ \\=\dfrac{3x^2}{x^2-4}\\ \\=3\dfrac{x^2-4+4}{x^2-4}\\ \\=3\left(1+\dfrac{4}{x^2-4}\right)\\ \\=3+\dfrac{12}{(x-2)(x+2)}[/tex]
This function is undefined when the denominator is equal to 0. The denominator is equal to 0 when x = 2 or x = -2, so two vertical asymptotes are x = 2 and x = -2.
The horizontal asymptote is y = 3.
Answer:
A
Step-by-step explanation:
Its the first one on edgeniuty (trash website)
