The speed of a moving bullet can be deter-
mined by allowing the bullet to pass through
two rotating paper disks mounted a distance
81 cm apart on the same axle. From the
angular displacement 13.7° of the two bul-
let holes in the disks and the rotational speed
432 rev/min of the disks, we can determine
the speed of the bullet.

Respuesta :

Answer:

[tex]v=16.806\ m/s[/tex]

Explanation:

Rotational Motion

An object is said to have rotational motion is it moves at the same distance to a fixed point called the center. The distance is called radio and the number of revolutions (or radians) it makes over time is called angular speed. Knowing the angle [tex]\theta[/tex] it makes in a certain time t, the angular speed is

[tex]\displaystyle w=\frac{\theta}{t}[/tex]

If we wanted to know the time it takes to describe some angle, we solve for t

[tex]\displaystyle t=\frac{\theta}{w}..........[1][/tex]

Two rotating paper disks are mounted at a distance of x= 81 cm = 0.81 m. If we knew the time the bullet take from one to the other, we could determine the speed of the bullet

[tex]\displaystyle v=\frac{x}{t}.............[2][/tex]

We can determine the time taken between the disks knowing their angular speed and the angle formed in the interval. Replacing the time from [1] into [2]

[tex]\displaystyle v=\frac{x}{\frac{\theta}{w}}[/tex]

[tex]\displaystyle v=\frac{xw}{\theta}[/tex]

We have the values

[tex]\theta=13.7^o=13.7/(2\pi)=2.18\ rad[/tex]

[tex]w=432\ rev/min=432*2\pi /60=45.239\ rad/s[/tex]

Thus

[tex]\displaystyle v=\frac{(0.81)(45.239)}{2.18}[/tex]

[tex]\boxed{v=16.806\ m/s}[/tex]