Answer:
The solution is the point (18,0)
Step-by-step explanation:
we have
[tex]y=-\frac{1}{3}x+6[/tex] -----> equation A
[tex]y=\frac{1}{3}x-6[/tex] -----> equation B
Solve the system by substitution
substitute equation B in equation A
[tex]\frac{1}{3}x-6=-\frac{1}{3}x+6[/tex]
solve for x
Adds (1/3)x both sides
[tex]\frac{1}{3}x-6+\frac{1}{3}x=6[/tex]
[tex]\frac{2}{3}x-6=6[/tex]
Adds 6 both sides
[tex]\frac{2}{3}x=6+6[/tex]
[tex]\frac{2}{3}x=12[/tex]
[tex]x=12(3)/2\\x=18[/tex]
Find the value of y
substitute the value of x in equation A or equation B
[tex]y=-\frac{1}{3}(18)+6=0[/tex]
therefore
The solution is the point (18,0)
