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Which expression is equivalent to RootIndex 3 StartRoot 32 x Superscript 8 Baseline y Superscript 10 Baseline EndRoot?

Respuesta :

Answer:

The equivalent expression to the given expression is [tex]\sqrt[3]{32x^8y^{10}}=2x^2y^3\sqrt[3]{4x^2y}[/tex]

Step-by-step explanation:

The given expression is [tex]\sqrt[3]{32x^8y^{10}}[/tex]

To find the equivalent expression:

[tex]\sqrt[3]{32x^8y^{10}}=(32x^8y^{10})^{\frac{1}{3}}[/tex]

We may write the above expression as below:

[tex]=(32^{\frac{1}{3}})((x^8)^{\frac{1}{3}})((y^{10})^{\frac{1}{3}})[/tex]

[tex]=(2)((4)^{\frac{1}{3}})(x^6)\times (x^2)(x^{\frac{2}{3}})(y^3)(y^{\frac{1}{3}})[/tex] (using square root properties)

[tex]=(2\sqrt[3]{4})(x^2\sqrt[3]{x^2})(y^3\sqrt[3]{y})[/tex] (combining the like terms and doing multiplication )

[tex]=2x^2y^3\sqrt[3]{4x^2y}[/tex]

Therefore [tex]\sqrt[3]{32x^8y^{10}}=2x^2y^3\sqrt[3]{4x^2y}[/tex]

Therefore the equivalent expression to the given expression is [tex]\sqrt[3]{32x^8y^{10}}=2x^2y^3\sqrt[3]{4x^2y}[/tex]

Answer:

C

Step-by-step explanation:

The Answer is C on Edge.