The average speed is 20.8 m/s
Explanation:
The average speed for the trip is given by:
[tex]v=\frac{d}{t}[/tex]
where
d is the distance covered
t is the time elapsed
For the trip in this problem, we have:
d = 187 km = 187,000 m is the distance travelled
The initial time is 10:00 pm while the arriving time is 12:30 am: this means that the time elapsed is 2.5 hours. Converting into seconds,
[tex]t = 2.5 h \cdot (60)(60)=9000 s[/tex]
Therefore, the average speed for the trip is
[tex]v=\frac{187,000}{9000}=20.8 m/s[/tex]
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