Answer:
168 grams of O2 are produced from 356.6g of Al2O3
Explanation:
Calculate the moles of Al2O3
Given mass = 356.6
Molar mass of Al2O3 = 2(mass of Al) +3(mass of O)
= 2(27) + 3(16)
=102 g/mol
[tex]mole =\frac{given\ mass}{ Molar\ mass}[/tex]
[tex]mole =\frac{356.6}{102}[/tex]
= 3.5 mole
The balanced equation for the equation is :
[tex]4Al+3O_{2}\rightarrow 2Al_{2}O_{3}[/tex]
2 mole of Al2O3 will give 3 mole of Oxygen
1 mole of Al2O3 = 3/2 = 1.5 mole of Oxygen
3.5 mole of Al2O3 = (1.5 x 3.5 ) mole of Oxygen
3.5 mole of Al2O3 = 5.25 moles of oxygen
Use,
[tex]given\ mass= Molar\ mass\times moles[/tex]
Molar mass of O2 = 16(2) = 32 g/mol
[tex]given\ mass= 32\times 5.25[/tex]
= 168 g
