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contestada

Find the sum of the first 8 terms of the geometric series, if the first term is 3 and the common
ratio is 4.

Respuesta :

Answer:

65535

Step-by-step explanation:

The sum to n terms of a geometric sequence is

[tex]S_{n}[/tex] = [tex]\frac{a(r^n-1)}{r-1}[/tex]

where a is the first term and r the common ratio, thus

[tex]S_{8}[/tex] = [tex]\frac{3(4^8-1|)}{4-1}[/tex]

                        = [tex]\frac{3(4^8-1)}{3}[/tex]

                        = [tex]4^{8}[/tex] - 1 = 65536 - 1 = 65535