Answer:
Francesca had [tex] \$\frac{139}{20} \ \ OR \ \ \$6\frac{19}{20}[/tex] money left for gift C.
Step-by-step explanation:
Given:
Total money to spent on gift = $20
Money Spent on gift A = [tex]\$ 8\frac{1}{4}[/tex]
[tex]\$ 8\frac{1}{4}[/tex] can Rewritten as [tex]\$\frac{33}{4}[/tex]
Money Spent on gift A = [tex]\$\frac{33}{4}[/tex]
Money Spent on gift B = [tex]\$ 4\frac{4}{5}[/tex]
[tex]\$ 4\frac{4}{5}[/tex] can Rewritten as [tex]\$\frac{24}{5}[/tex]
Money Spent on gift B = [tex]\$\frac{24}{5}[/tex]
We need To find the Money left for gift C.
Solution:
Money left for gift C can be calculated by subtracting Money Spent on gift A and Money Spent on gift B with Total Money spent on gifts.
Framing in equation form we get;
Money left for gift C = [tex]20-\frac{33}{4}-\frac{24}{5}[/tex]
Now taking LCM for making the denominator common we get;
Money left for gift C =[tex]\frac{20\times 20}{20}-\frac{33\times5}{4\times5}-\frac{24\times4}{5\times4}= \frac{400}{20}-\frac{165}{20}-\frac{96}{20}=\frac{400-165-96}{20} = \$\frac{139}{20} \ \ OR \ \ \$6\frac{19}{20}[/tex]
Hence Francesca had [tex] \$\frac{139}{20} \ \ OR \ \ \$6\frac{19}{20}[/tex] money left for gift C.