Answer:
Therefore,
[tex]x=b[/tex] is the required value.
Step-by-step explanation:
If a ≠ 0, a ≠ 1 and
[tex]\dfrac{ax-b}{a-1} =b\\\\[/tex]
To Find:
x = ?
Solution:
[tex]\dfrac{ax-b}{a-1} =b\\\\ax-b=b(a-1)\\[/tex]
Applying Distributive Property i.e A(B+C)=AB+AC we get
[tex]ax-b=b\times a-b\times 1\\\\ax-b=b\times a-b\\\\ax=b\times a-b+b\\\\ax=b\times a\\\\x=\dfrac{ba}{a}\\a\neq 0\ a\neq 1\\a\ will\ cancel\\\\ x=b[/tex]
Therefore,
[tex]x=b[/tex] is the required value.
