A force of 100 N is applied to a crate at an angle of 60° to the horizontal surface.
The force causes the crate to move 2 m across the floor. How much work is done
on the crate?
50 J
100 J
2003

Respuesta :

Answer:

100 J

Explanation:

Given:

Force acting on the crate is, [tex]F=100\ N[/tex]

Displacement of the crate is, [tex]S=2\ m[/tex]

Angle between the direction of force and displacement is, [tex]\theta=60\°[/tex]

Now, work done by a force 'F' causing a displacement 'S' such that the angle between the force and displacement is [tex]\theta[/tex] is given as:

[tex]Work=F\times S\times \cos\theta[/tex]

Now, plug in 100 N for 'F', 2 m for 'S', and 60° for [tex]\theta[/tex]. This gives,

[tex]Work=(100\ N)(2\ m)(\cos(60))\\\\Work=(200\times 0.5)\ \textrm{N-m}\\\\Work=100\ J[/tex]

Therefore, the work done by the force is 100 J.