Answer:
The solution is x=6
Step-by-step explanation:
we know that
The formula to solve a quadratic equation of the form
[tex]ax^{2} +bx+c=0[/tex]
is equal to
[tex]x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}[/tex]
in this problem we have
[tex]x^{2} -12x+36=0[/tex]
so
[tex]a=1\\b=-12\\c=36[/tex]
substitute in the formula
[tex]x=\frac{-(-12)\pm\sqrt{-12^{2}-4(1)(36)}} {2(1)}[/tex]
[tex]x=\frac{12\pm\sqrt{0}} {2}[/tex]
[tex]x=\frac{12} {2}=6[/tex]
