358 tickets to the school basketball game on Friday were sold.Students tickets were $1.50 and non-student tickets were $3.25. The school made $752.25.Write and solve a system of equations to determine how many of each ticket was sold.

Respuesta :

235 student tickets and 123 non-student tickets were sold.

Step-by-step explanation:

Given,

Total number of tickets sold = 358

Total revenue generated = $752.25

Cost of student ticket = $1.50

Cost of non-student ticket = $3.25

Let,

x represent the number of student tickets sold.

y represent the number of non-student tickets sold.

According to given statement;

x+y=358    Eqn 1

1.50x+3.25y=752.25    Eqn 2

Multiplying Eqn 1 by 1.50

[tex]1.50(x+y=358)\\1.50x+1.50y=537\ \ \ Eqn 3\\[/tex]

Subtracting Eqn 3 from Eqn 2

[tex](1.50x+3.25y)-(1.50x+1.50y)=752.25-537\\1.50x+3.25y-1.50x-1.50y=215.25\\1.75y=215.25[/tex]

Dividing both sides by 1.75

[tex]\frac{1.75y}{1.75}=\frac{215.25}{1.75}\\y=123[/tex]

Putting y=123 in Eqn 1

[tex]x+123=358\\x=358-123\\x=235[/tex]

235 student tickets and 123 non-student tickets were sold.

Keywords: linear equation, elimination

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