Respuesta :
Answer:
The final velocity of the stone = 19.6 m/s
Explanation:
We have to find the velocity of a stone dropped from a tower which hits the pavement in two seconds.
As a stone is released from the top of a building , it undergoes uniform acceleration of gravity and speeds up and hits the ground with a certain speed.
We have the equation,
v = u + gt
v = final velocity
u = initial velocity
t = time taken
g = 9.8 m/[tex]s^{2}[/tex]
Substituting these values we get
v = 0 + 9.8[tex]\times 2[/tex]
v = 19.6 m/s
The final velocity of the stone = 19.6 m/s
