Respuesta :
Answer:
The percent composition of each element are :
1. Th(SO4)2 :
Th = 54.704% , S = 15.119% , O = 30.1759 %
2.Ca3(PO4)2
Ca = 38.76% , P = 19.97% , O = 41.265%
3.C6H12O6
C = 40.0% , H = 6.72% , O = 53.29%
Explanation:
Formula calculate the percent composition
[tex]% composition =\frac{mass\ of\ given\ element}{Molar\ mass}[/tex]
Molar mass of Th(SO4)2 = Mass of Th + 2(mass of S) + 8(mass of O)
= 232.03 + 2(32.06) + 8(16)
=232.03 +64.12+128
= 424.16
[tex]% Th=\frac{mass\ of\ Th}{424.16}[/tex]
[tex]=\frac{232.03}{424.16}[/tex]
= 54.704%
[tex]% S=\frac{2(mass\ of\ S)}{424.16}[/tex]
[tex]=\frac{64.12}{424.16}[/tex]
= 15.119%
[tex]% O=\frac{8(mass\ of\ O)}{424.16}[/tex]
[tex]= \frac{128}{424.16}[/tex]
= 30.17%
2.Ca3(PO4)2
Molar mass of Ca3(PO4)2 = 3(Mass of Ca) + 2(mass of P) + 8(mass of O)
= 3(40) + 2(30 .9) + 8(16)
= 120 + 61.8 + 128
=310.176
[tex]% Ca =\frac{3(mass\ of\ Ca)}{310.176}[/tex]
[tex]=\frac{120}{424.16}[/tex]
38.76%
[tex]% P=\frac{2(mass\ of\ P)}{310.176}[/tex]
[tex]=\frac{61.8}{310.176}[/tex]
= 19.97%
[tex]% O=\frac{8(mass\ of\ O)}{310.176}[/tex]
[tex]=\frac{128}{424.16}[/tex]
= 41.26 %
3.
C6H12O6
Molar mass of C6H12O6 = 6(Mass of C) + 12(mass of O) + 6(mass of O)
= 6(12) + 12(1) + 6(15.99)
=180
[tex]% O=\frac{6(mass\ of\ O)}{180}[/tex]
[tex]=\frac{95.94}{180}[/tex]
= 53.28%
[tex]% C=\frac{6(mass\ of\ C)}{180}[/tex]
[tex]% C=\frac{72}{180}[/tex]
= 40%
[tex]% H=\frac{12(mass\ of\ C)}{180}[/tex]
[tex]=\frac{(12}{180}[/tex]
= 6.713%
