The surface temperature of a red star is lower than the surface temperature of a yellow star.
Explanation:
For a red star, the peak of the wavelength of the emitted light is in the red spectrum, therefore the average peak wavelength is:
[tex]\lambda = 680 nm = 680 \cdot 10^{-9} nm[/tex]
The corresponding temperature at the surface of the star can be found by using Wien's displacement law:
[tex]T=\frac{b}{\lambda}[/tex]
where
[tex]b=2.898\cdot 10^{-3} m\cdot K[/tex] is a constant. Substituting, we find
[tex]T_r=\frac{2.898\cdot 10^{-3}}{680\cdot 10^{-9}}\sim 4300 K[/tex]
For a yellow star, the peak of the wavelength of the emitted light is in the yellow spectrum, therefore the average peak wavelength is:
[tex]\lambda = 580 nm = 580 \cdot 10^{-9} nm[/tex]
So we can use again the same equation to find the corresponding surface temperature of a yellow star:
[tex]T_y=\frac{2.898\cdot 10^{-3}}{580\cdot 10^{-9}}\sim 5000 K[/tex]
Therefore, we see that the surface temperature of a red star is lower than the surface temperature of a yellow star.
Learn more about temperature:
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