Answer:
The time period = [tex]\frac{\pi}{2}[/tex]
Explanation:
Let's assume a pendulum of length l and time period T.
Then the equation for the time period, T = [tex]2\pi \sqrt{\frac{l}{g} }[/tex]
Here g = acceleration due to gravity = 9.8 m/[tex]s^{2}[/tex]
Here we are given a simple pendulum of length 2.45 m.
Substitute this value of length in the given equation,
T = [tex]2\pi \sqrt{\frac{l}{g} }[/tex]
= [tex]2\pi \sqrt{\frac{2.45}{9.8}}[/tex]
= [tex]\frac{\pi }{2}[/tex]
Hence the time period = [tex]\frac{\pi}{2}[/tex]
