Answer:
0.200 m NaOH has the highest boiling point (option B)
Explanation:
Step 1: Data given
The elevation of boiling point is proportional to the number of ions in solution.
The van't Hoff factor, i, is a measure of how many ions are produced from one molecule of the solute. For nonelectrolytes, i = 1).
We can compute the product of the van't Hoff factor and the molality for each of the solutes in the list:
a. 0.100 m CaCl2
⇒ CaCl ⇒ Ca^2+ + 2Cl- : van't Hoff factor = 3
0.100 * 3 = 0.300
b. 0.200 m NaOH
⇒ NaOH ⇒ Na+ + OH- : Van't Hoff factor = 2
0.200 * 2 = 0.400
c. 0.050 m K2SO4
⇒ K2SO4 = 2K+ + SO4^2- : Van't Hoff factor = 3
0.050 * 3 = 0.150
d. 0.050 m Al2(SO4)3
⇒ Al2(SO4)3 ⇒ 2Al^3+ + 3SO4^2- : Van't Hoff factor = 5
0.050 * 5 = 0.250
e. 0.200 m CH3OH
methanol is a non-emektrolyte Van't hoff factor = 1
0.200 * 1 = 0.200
Since the highest result is from 0.200 m NaOH, means this has the highes boiling point. ( Option B) is correct)
