The height above the ground the kite is flying is 62.28 meters
Solution:
Given that Brains kite is flying above a field at the end of 65 m of string
The figure is attached below
ABC is a right angled triangle
Let AB be the height at which the kite is flying above the ground
AB = h = ?
Given that angle elevation to the kite measures 70 degrees
Thus angle C = 70 degrees
Brains kite is flying above a field at the end of 65 m of string
Therefore, AB = 65 meters
We know that,
[tex]sin \theta = \frac{opposite}{hypotenuse}[/tex]
Here,
[tex]\theta = 70^{\circ}[/tex]
Opposite = AB = h
Hypotenuse = AC = 65 meters
Therefore,
[tex]sin 70 = \frac{h}{65}\\\\0.9397 = \frac{h}{65}\\\\h = 0.9397 \times 65\\\\h = 61.08[/tex]
To find the height above the ground we have to add 1.2 m to 61.08
height above the ground = 61.08 + 1.2 = 62.28 meters
Thus the height above the ground the kite is flying is 62.28 meters
