Answer:
[tex]\frac{x-1}{0} =\frac{y-0}{0} \frac{z+3}{1}[/tex]
Step-by-step explanation:
given that a line is perpendicular to xy plane.
Also the line passes through (1,0,-3)
In three dimension rectangular coordinates we have 3 mututally perpendicular lines as three axes.
Here since the given line is perpendicular to xy plane, and equation of xy plane is z=0 we find that the required line has direction ratios as (0,0,1)
(since 0.x+0.y+1.z=0 is the plane equation normal has (0.0,1)
It passes through (1,0,-3)
So in parametrical form we write equation as
[tex]\frac{x-1}{0} =\frac{y-0}{0} \frac{z+3}{1}[/tex]
