Answer:
[tex]\large\boxed{x=-11\dfrac{4}{5}}[/tex]
Step-by-step explanation:
Ten times the sum of half a number x and 7 is 11:
[tex]10\cdot\left(\dfrac{1}{2}x+7\right)=11\qquad\text{use the distributive property}\\\\(10\!\!\!\!\!\diagup^5)\left(\dfrac{1}{2\!\!\!\!\diagup_1}x\right)+(10)(7)=11\qquad\text{simplify}\\\\5x+70=11\qquad\text{subtract 70 from both sides}\\\\5x+70-70=11-70\\\\5x=-59\qquad\text{divide both sides by 5}\\\\\dfrac{5x}{5}=\dfrac{-59}{5}\\\\x=-11\dfrac{4}{5}[/tex]
