Answer
given,
initial speed of the car (v₁)= 19.8 mi/h
final speed of the car (v₂)= 59.9 mi/h
a) initial momentum = m v₁
P₁ = 19.8 m
final final momentum = m v₂
P₂ = 59.9 m
ratio = [tex]\dfrac{P_2}{P_1}[/tex]
=[tex]\dfrac{59.9 m}{19.8 m}[/tex]
ratio of momentum=[tex]\dfrac{P_2}{P_1}=3.025[/tex]
b) initial kinetic energy= 1/2 m v₁²
K₁ = 196.02 m
final kinetic energy= 1/2 m v₂²
K₂ = 1794.005 m
ratio = [tex]\dfrac{K_2}{K_1}[/tex]
=[tex]\dfrac{1794.005 m}{196.02 m}[/tex]
ratio of Kinetic energy=[tex]\dfrac{P_2}{P_1}=9.15[/tex]
