Two cyclists start at the same point and travel in opposite directions. One cyclist travels 10 mih slower than the other. If the two cyclists are 104 miles apart after 4 hours, what is the rate of each cyclist?

Respuesta :

The speed of slower cyclist is 8 miles per hour

The speed of faster cyclist is 18 miles per hour

Solution:

One cyclist travels 10 min slower than the other

Let "x" be the speed of slower cyclist

Then, x + 10 is the speed of faster cyclist

The distance is given by formula:

[tex]distance = speed \times timetaken[/tex]

Distance of slower cyclist = [tex]x \times 4[/tex]

Distance of slower cyclist = 4x

Distance of faster cyclist = [tex](x + 10) \times 4 = 4x + 40[/tex]

The two cyclists are 104 miles apart after 4 hours

4x + 4x + 40 = 104

8x + 40 = 104

8x = 104 - 40

8x = 64

x = 8

Thus rate of each cyclist is:

speed of slower cyclist = x = 8 miles per hour

speed of faster cyclist = x + 10 = 8 + 10 = 18 miles per hour