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At some instant, the blood pressure in the heart is 1.5 ×10^4 Pa. Assume the density of blood is the same as water. What is the pressure in an artery 0.50 m below the heart, treating the blood as a nonviscous fluid?

Respuesta :

Answer:

P₂ = 1.99 x 10⁴ Pa

Explanation:

given,

blood pressure at an instant = 1.5 x 10⁴ Pa

density of blood is equal density of water = 1000 kg/m³

depth = 0.5 m

Pressure below the heart = ?

[tex]P_2 = P_1 + \rho g h[/tex]

P₂ is the required pressure at 0.5 m depth

P₁ is the blood pressure in heart

g is the  acceleration due to gravity

now,

[tex]P_2 = 1.5\times 10^4 + 1000\times 9.8 \times 0.5[/tex]

P₂ = 19900 Pa

P₂ = 1.99 x 10⁴ Pa

Hence, the pressure below 0.5 m is equal to P₂ = 1.99 x 10⁴ Pa

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