Two trains leave towns 798 kilometers apart at the same time and travel toward each other. One train travels 22 kmh slower than the other. If they meet in 3 hours, what is the rate of each train?

Respuesta :

The rate of faster train is 144 kilometer per hour and rate of slower train is 122 kilometers per hour.

Step-by-step explanation:

Given,

Total distance = 798 kilometers

Let,

speed of faster train = x

speed of slower train = x-2

Time = 3 hours

Distance = Speed*Time

Distance covered by faster train = 3x

Distance covered by slower train = 3(x-22) = 3x-66

As they both traveled combined distance, therefore,

[tex]3x+(3x-66)=798\\3x+3x-66=798\\6x=798+66\\6x=864[/tex]

Dividing both sides by 6

[tex]\frac{6x}{6}=\frac{864}{6}\\x=144[/tex]

The speed of faster train is 144 km/h

Speed of slower train = x-22 = 144-22 = 122 km/h

The rate of faster train is 144 kilometer per hour and rate of slower train is 122 kilometers per hour.

Keywords: distance, speed

Learn more about distance at:

  • brainly.com/question/3398261
  • brainly.com/question/3614284

#LearnwithBrainly