Answer:
20.
Step-by-step explanation:
This can be solved using combination technique. Since we have to choose 3 out of 6 and their order is not considered. Thus,
6 combination 3
= 6C3
= [tex]\frac{6!}{3!*(6-3)!}[/tex]
= [tex]\frac{6*5*4*3!}{3!*3!}[/tex]
= [tex]\frac{6*5*4}{3*2*1}[/tex]
= [tex]\frac{6*5*4}{6}[/tex]
= 5*4
= 20 ANSWER