Question is Incomplete,Complete question is given below;
Figure ABCD is a parallelogram.
What are the lengths of line segments AB and BC?
AB = 4; BC = 16
AB = 4; BC = 8
AB = 10; BC = 20
AB = 10; BC = 28
Answer:
AB = 10 ;BC =28.
Step-by-step explanation:
The Diagram is missing in the question we have attached the diagram for your reference.
Given:
AB = [tex]3y -2[/tex]
DC = [tex]y+6[/tex]
BC = [tex]x+12[/tex]
AD = [tex]2x-4[/tex]
We need to find the lengths of AB and BC.
Solution:
Since given that Figure ABCD is a parallelogram.
"The opposite side of parallelogram are equal."
Hence we can say that;
AB = DC
Substituting the value we get;
[tex]3y-2=y+6[/tex]
Combining the like terms we get;
[tex]3y-y=6+2\\\\2y =8[/tex]
Dividing both side by 2 we get;
[tex]\frac{2y}{2}=\frac{8}{2} \\\\y=4[/tex]
Now AB = [tex]3y -2 =3\times 4-2 =12-2 =10[/tex]
Also
BC = AD
Substituting the value we get;
[tex]x+12=2x-4[/tex]
Combining the like terms we get;
[tex]2x-x=12+4\\\\x =16[/tex]
Now BC = [tex]x+12 =16+12 =28[/tex]
Hence AB = 10 and BC =28.
